(98x^2)+4x-2=0

Solution for (98x^2)+4x-2=0 equation:

(98x^2)+4x-2=0

a = 98; b = 4; c = -2;
Δ = b2-4ac
Δ = 42-4·98·(-2)
Δ = 800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{800}=\sqrt{400*2}=\sqrt{400}*\sqrt{2}=20\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-20\sqrt{2}}{2*98}=\frac{-4-20\sqrt{2}}{196}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+20\sqrt{2}}{2*98}=\frac{-4+20\sqrt{2}}{196}
$